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Answer:
(2,10) or x=2 y=10
Step-by-step explanation:
<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>
5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)
5x=2y-10 (Divide the 5 from the x)
x=2/5y-2
<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>
3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)
6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)
36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)
y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)
y=10
<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>
5x-2(10)=-10 (Multiple 2 by 10)
5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)
5x=10 ( Divide 10 by 5)
x= 2
<em>4. If needed, plug in the values of x and y to check your solution.</em>
Hope this could help! :)
8 + 3b= -13
-8. -8
3b= -21
Divide by 3
B= -7
The answer is A. one of the zeros is x = -1
Answer:
(x+6)(x+6)
(x+6)^2
Always remember this identity
(a+b)^2 = a^2 + b^2 + 2ab
So, Now take x=a , 6 =b
Substitute above values
x^2 + 36 +2(x)(6)
=x^2 +36 +12x
=x(x+12) +36
