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Snezhnost [94]
3 years ago
8

THIS IS HARD FOR M I NEED HELP!!!!!

Mathematics
2 answers:
KiRa [710]3 years ago
6 0
Find what x would be if y is 7, them find what x will be if y is 9.
If y is 7, x will be 2.
If y is 9, x will be 4.
So the answer is 2,4 or A.
Taya2010 [7]3 years ago
4 0

A domain x ∈ {2, 4 }

To find the domain, that is the values of x that produce the values in the range , solve for x , that is

x + 5 = 7 ⇒ x = 7 - 5 = 2

x + 5 = 9 ⇒ x = 9 - 5 = 4



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How would I solve the rest of this?
GalinKa [24]

it would be y = -12/5. Hes the work. hope this helps!





5 0
3 years ago
4.624 to the nearest 10m
lianna [129]
4620 m<span>hope this helps </span>
7 0
3 years ago
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

sorry it's just a guess i'm like 99% sure tho
8 0
3 years ago
Find the value of x. <br><br><br><br><br><br><br> 60o<br><br> 79o<br><br> 70o<br><br> 47o
LekaFEV [45]
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3 0
3 years ago
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot  represents class first. From the first box plot, we get

\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

Second box plot  represents class second. From the second box plot, we get

\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0
3 years ago
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