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3 years ago

What is the interquartile range of the data set?

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data. (1, 2, 5, 6, 7<span>), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18. Step 5: Subtract Q1 from Q3 to find the interquartile range</span>

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(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

<u>Step-by-step explanation:</u>

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

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Given: RE = 2AR and RT = 2GR<br> Prove : ∆GAR ~ ∆TER

marysya [2.9K]

Answer:

Statement:- Reason:-

RE=2AR Given

RT=2GR

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∠DRA≅∠TRE Vertical angles

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RE/AR=RT/GR proportionality of sides

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ΔGAR≈ΔTER SAS similarity theorem

<h3><u>-------------------------</u></h3><h3><u>Hope it helps...</u></h3><h3><u>Have a great day!! </u></h3>

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