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alukav5142 [94]
3 years ago
12

The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been fikked 4 feet deep. How many more

cubic feet of water are needed to finish filling the pool?
Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

600 cubic feet of water

Step-by-step explanation:

If the pool is filled 4 feet and the pool is 5 feet deep, that leaves 1 foot of depth left to fill. This makes the volume equation 30 x 20 x 1 which equals 600.

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2 years ago
Which is more, 6 inches or 1 foot? 6 inches 1 foot Neither, they are equal ​
kodGreya [7K]
1 foot is more
6 inches is 0.5 feet
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3 years ago
Read 2 more answers
The equation of a line of best fit relating the number of cats c at an animal shelter to the number
WINSTONCH [101]
ANSWER 155 cats

Step by step explanation

No. of dogs = 50=d
No. of cats = 3.5x50- 20
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8 0
3 years ago
The three side lengths of a triangle are represented by x, (x+10), and (x+5) units. The perimeter of the triangle is 75 units. W
ollegr [7]

Answer:

if the perimeter is 75 units and the side lengths are x + 10 and x + 5 it would probably be plus 60 to make it 75

8 0
3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
2 years ago
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