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alukav5142 [94]

3 years ago

12

The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been fikked 4 feet deep. How many more

cubic feet of water are needed to finish filling the pool?

1 answer:

Vesna [10]3 years ago

8 0

Answer:

600 cubic feet of water

Step-by-step explanation:

If the pool is filled 4 feet and the pool is 5 feet deep, that leaves 1 foot of depth left to fill. This makes the volume equation 30 x 20 x 1 which equals 600.

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ivanzaharov [21]

$\begin{array}{l}\text{Let\ x\ be\ the\ third\ side,\ then,\ by\ Pitagoras}\\\\x^{2} +5^{2} =\left(\sqrt{61}\right)^{2}\\\\\Longrightarrow x^{2} =61-25\\\\\Longrightarrow x=\sqrt{36} =6\end{array}$

6 0

2 years ago

Which is more, 6 inches or 1 foot? 6 inches 1 foot Neither, they are equal

kodGreya [7K]

1 foot is more
6 inches is 0.5 feet

6 0

3 years ago

Read 2 more answers

The equation of a line of best fit relating the number of cats c at an animal shelter to the number

WINSTONCH [101]

ANSWER 155 cats

Step by step explanation

No. of dogs = 50=d
No. of cats = 3.5x50- 20
=175-20
=155 cats

8 0

3 years ago

The three side lengths of a triangle are represented by x, (x+10), and (x+5) units. The perimeter of the triangle is 75 units. W

ollegr [7]

Answer:

if the perimeter is 75 units and the side lengths are x + 10 and x + 5 it would probably be plus 60 to make it 75

8 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago