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3 years ago

True or false? A triangle can be formed with side lengths of 2 in, 3 in, and 6 in.

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

hi,

the sum of any 2 sides of a triangle must be greater than the measure of the third side.

2+3=5

FALSE

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Find the equation of the line that passes through the following points. Write the equation in slope-intercept form.

ra1l [238]

Answer:

The equation in the slope-intercept form will be:

y = 1/4x - 7

Step-by-step explanation:

Given the points

(-4.-8)

(-8, -9)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:-8\right),\:\left(x_2,\:y_2\right)=\left(-8,\:-9\right)$

$m=\frac{-9-\left(-8\right)}{-8-\left(-4\right)}$

$m=\frac{1}{4}$

We know that the slope-intercept of line equation is

$y=mx+b$

where m is the slope and b is the y-intercept

substituting m = 1/4 and the point (-4, -8) to find the y-intercept 'b'

y = mx+b

-8 = 1/4(-4)+b

-8 = -1 + b

b = -8+1

b = -7

so the y-intercept = b = -7

substituting m = 1/4 and b = -7 in the slope-intercept form of line equation

y = mx+b

y = 1/4x + (-7)

y = 1/4x - 7

Thus, the the equation in slope-intercept form will be:

y = 1/4x - 7

6 0

3 years ago

Which equation is represented by the graph below?

jekas [21]

Answer: D

Step-by-step explanation:

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3 years ago

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Form quadratic functions given the following information:

nignag [31]

Answer:

$f(x)=-\frac{4}{7}(x-\sqrt{2}-3)(x+\sqrt{2}-3)$

$f(x)=-\frac{4}{7}(x^2-6x+7)$

Step-by-step explanation:

we have

f(3+√2 )=f(3− √2 )=0

x1=3+√2 and x2=3−√2 are the roots or x-intercepts of the quadratic equation

The quadratic equation in factored form is equal to

$f(x)=a(x-x1)(x-x2)$

substitute

$f(x)=a(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

Find the value of the coefficient a

Remember that

f(1)=−8

For x=-1 -----> f(x)=-8

substitute

$-8=a(-1-(3+\sqrt{2}))(-1-(3-\sqrt{2}))$

solve for a

$-8=a(-4-\sqrt{2}))(-4+\sqrt{2}))$

apply difference of squares

$-8=a(14)$

$a=-\frac{4}{7}$

therefore

$f(x)=-\frac{4}{7}(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

$f(x)=-\frac{4}{7}(x-\sqrt{2}-3)(x+\sqrt{2}-3)$

simplify

Applying distributive property

$f(x)=-\frac{4}{7}(x^2+\sqrt{2}x-3x-\sqrt{2}x-2+3\sqrt{2}-3x-3\sqrt{2}+9)$

$f(x)=-\frac{4}{7}(x^2-6x+7)$

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natali 33 [55]

Answer:

whats the question

Step-by-step explanation:

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3 years ago

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Simplify 4(7-10)^/(-6)-5*(-2)

trasher [3.6K]

Use your calculator put all of them together then you’ll get your answer

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3 years ago