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saw5 [17]
3 years ago
7

Find the equation of the line that passes through the following points. Write the equation in slope-intercept form.

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

The equation in the slope-intercept form will be:

y  = 1/4x - 7

Step-by-step explanation:

Given the points

  • (-4.-8)
  • (-8, -9)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:-8\right),\:\left(x_2,\:y_2\right)=\left(-8,\:-9\right)

m=\frac{-9-\left(-8\right)}{-8-\left(-4\right)}

m=\frac{1}{4}

We know that the slope-intercept of line equation is

y=mx+b

where m is the slope and b is the y-intercept

substituting m = 1/4 and the point (-4, -8) to find the y-intercept 'b'

y = mx+b

-8 = 1/4(-4)+b

-8 = -1 + b

b = -8+1

b = -7

so the y-intercept = b = -7

substituting m = 1/4 and b = -7 in the slope-intercept form of line equation

y = mx+b

y  = 1/4x + (-7)

y  = 1/4x - 7

Thus, the the equation in slope-intercept form will be:

y  = 1/4x - 7

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<h3>What is the Law of Sines?</h3>

The law of sines is given as: sin A/a = sin B/b = sin C/c, which is used to solve a triangle.

Given the following:

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