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Tpy6a [65]
4 years ago
14

GIVING BRAINLIEST TO THE FIRST PERSON TO ANSWER!

Mathematics
2 answers:
Pie4 years ago
6 0

Answer:

\Large \boxed{\mathrm{Store \ D}}

Step-by-step explanation:

Store A is offering the tablet on sale at 15% off the regular price.

150 × (1 - 15%) = 127.5

Store B is offering a $25 coupon to be deducted from the regular price.

150 - 25 = 125

Store C is offering a rebate of $20.00 to purchasers.

150 - 20 = 130

Store D has the tablet on sale for $120.00.

Store D is offering the tablet at the lowest cost.

umka2103 [35]4 years ago
5 0

Answer: Store D

Step-by-step explanation:

Store A - 15% off:

$150 times 15/100 = 22.5

$150 - $22.50 = $127.50 so the price at store A is $127.50

Store B - $25 coupon

$150 - $25 = $125 so the price at store B is $125

Store C - $20 rebate

$150 - $20 = $130 so the price at store B is $130

Store D - $120

$120 is the lowest so the answer is Store D

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Answer:

The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.

Step-by-step explanation:

What gives the number "255,\!120" its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first \verb!5! to \verb!6! would give 2\mathbf{6}5,\!120 and increase the value of this number by 10,\!000. On the other hand, changing the second \verb!5!\! to \verb!6!\! would give 25\mathbf{6},\!120, which is an increase of only 1,\!000 compared to the original number.

The order of these two digits matter because the number "255,\!120" is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in 255,\!120\!:

\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}.

(Note that the index starts at 0 from the right-hand side.)

Using these weights, the value 255,\!120 can be written as the sum:

\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}.

As seen in this sum, the first "5" contributed 50,\!000 to the total value, while the second "5\!" contributed only 5,\!000.

Hence: The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.  

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