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3 years ago

What is the answer? 8 x 1/2 = ______

Mathematics

2 answers:

Sidana [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Another way to write this is 8/1 x 1/2. Then the answer would be 8/2. Simplify to get 4.

Harrizon [31]3 years ago

3 0

8 × 1/2 = 4!

Calculation steps:

8 ×

= 8 ×

8 × 1

1 × 2

8 ÷ 2

2 ÷ 2

= 4

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Let u = <9,4>, v = <-2,5> Find u + v.

love history [14]

Answer:

Step-by-step explanation:

You are given u = <9,4> and v = <-2,5>. You are asked to find u+v. all you need to do is to add them with their respective position. u+v = <9-2, 4+5>, u+v = <7,9>. This is the correct answer.

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3 years ago

What is an equation for the line with slope 2/3 and y-intercept 9

Contact [7]

The equation of a line is y-mx+b with m being slope and b being y-intercept. Using the values provided in your problem, your answer would be y=2/3x+9, or C.

6 0

3 years ago

Does anyone know the answer ?

Delicious77 [7]

The second one it's double.

5 0

4 years ago

Alice needs 3/7 kilograms of flour for making a cake. How many of flour does she needs for making 42 cakes?

Oduvanchick [21]

Hey there!

3/7 is needed for 1 cake

If she needs to make 42 cakes, then multiply the amount for 1 by 42

42 × 3/7 = 126/7 = 18

She needs 18 kilograms of flour to make 42 cakes

Hope this helps :)

3 0

3 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

4 years ago