Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:
Then, the probability that at most 1 car will require major engine repair next year is:
Step-by-step explanationifk:
186,624 I think
4*3=12
12*4=48
48*9=432
= 186,624!