Answer:
Step-by-step explanation:
Assuming that for each option, you play the same number of games,x
Let y represent the cost of playing x games using option A
Option A is to buy a membership card and pay $2 every time you go to the gym. The membership card costs $20. It means that
y = 20 + 2x
Let z represent the cost of playing x games using option B
Option B is to pay $4 each time you go. It means that
z = 4x
To determine how many games will be played before cost of option A equal to the cost of option B, we would equate y to z. It becomes
20 + 2x = 4x
4x - 2x = 20
2x = 20
x = 20/2 = 10
It will take 10 games for both to be the same
Answer:
Step-by-step explanation:
1. use distribution factor
(4x+3)(24+5x)
4x times 24 = 96
4x times 5x = 20x
3 times 24 = 72
3 times 5x = 15x
2. combine like terms
96 + 72 = 168
15x + 20x = 35x
35x + 168 or 168 + 35x
I may be wrong please check my answer. I may have a lapse in my algebra, or I may have misunderstood the problem. But this is what I can give you to the best of my knowledge.
To see how they are related, let us solve the two equations.
FIRST EQUATION
SECOND EQUATION
Hence the solutions to the two equations are ADDITIVE INVERSE of each other.
