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ivanzaharov [21]
3 years ago
7

Suppose b= 2a-16 and b= a+2. What is the value of a?

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
Subsitute
2a-16=b=a+2
2a-16=a+2
subtract a from boths ides
a-16=2
add 16
a=18
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Expand &amp; simplify <br> (2x+6)(x−9)
Alex777 [14]

Answer:

2x^2-12x-54

Step-by-step explanation:

First 2x times x along with 2x times -9

Second 6 times x  along with 6 times -9

2x^2-18x+6x-54

=2x^2-12x-54

8 0
2 years ago
Please help me! I will give Brainlylist
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Answer:

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2 years ago
Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d
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The answer is
q + d = 12
0.25q + 0.10d = 2.40


q - the number of quarters
d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
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3 0
3 years ago
What is 12/15 as a percent
jok3333 [9.3K]
The answer is 80% because 12/15 is 0.8
8 0
3 years ago
Read 2 more answers
Liang is ordering new tires for his car. The tires he has have a circumference of 28π inches and a wheel rim with a circumferenc
skelet666 [1.2K]

The radius of tire is larger than radius of wheel by 5 inch

Step-by-step explanation:

We know that circumference of the circle is 2πr where “r” is the radius of the circle

Circumference refers to the dimension of the periphery of the circle. Since tires are put on the periphery of the wheel hence, we considered the circumferential aspect of the wheel.

Given-

Circumference of tires= 28π inches

2πr= 28π cancelling the common term “π” both sides

r (radius of the tires) = 14 inches

Circumference of the wheel rims= 18π

2πr= 18π cancelling the common term “π” both sides

r (radius of the tires) = 9 inches

Difference between the radius= 14-9= 5 inches

Hence, the difference between the radius of tires and the radius of the wheels is 5 inches

 

4 0
3 years ago
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