So this is taking this equation and plugging it into the quadratic formula -b+- (sqrt (b^2)-(4)ac)/2a so your A value is 1 B value is 3 and C value is -5 so it’s B&E
4x + 3y = 54 (1)
3x + 9y = 108 (2)
Multiply (1) by (-3)
-12x - 9y = -162
3x + 9y = 108
---------------------add
-9x = -54
x = 6
plug x = 6 into (1) to find y
4(6) + 3y = 54
24 + 3y = 54
3y = 30
y = 10
Answer
(6 , 10)
Hope it helps.
Answer:
C
Step-by-step explanation:
If you need the explanation tell me
:D
Answer:
Velocity (against wind) = 1,890 / 3 = 630 mph
Velocity (with the wind) = 1,890 / 2.5 = 756 mph
Plane speed (still air) = 630 + wind speed
Plane speed (still air) = 756 - wind speed
Adding both equations equals
2 * Plane speed (still air) = 1,386
Plane Speed = 693 mph
Source: https://www.1728.org/veloccal.htm
Step-by-step explanation:
13 By the factor theorem, if the function is divisible by x - 3 then f(3) = 0. So we have:-
2(3)^3 + k(3)^2 + 7(3) - 3 = 0
9k = 3 - 21 - 54 = -72
k = -72/9 = -8 answer
14. Similarly , f(-4) = 0 , so we have:-
(-4)^3 + 9(-4)^2 + k(-4) - 12 = 0
-64 + 144 - 4k - 12 = 0
4k = -64 + 144 - 12 = 68
k = 68/4
k = 17 answer
