Sum of linear pair of angles = 180°
so
<EFG + <GFH = 180°
2n + 21 + 4n + 15 = 180°
6n + 36 = 180°
6n = 144
n = 24
<EFG = 2(24) + 21 = 69°
<GFH = 4n + 15 = 4(24) + 15 = 111°
The third graph represents the data because the values in the table are identical to the ones plotted on that graph.
Answer:
$1,391.25
Step-by-step explanation:
Noon would be 12:00 PM which would be 4 hours ahead of 8:00 AM
We subtract $8,821 by $3,256 to get the amount earned between 8:00 AM and 12:00 PM
$8,821 - $3,256
= $5,565
The find the average taken in within those 4 hours we will have to divide the money earned by the hours
$5,565/4
= $1,391.25
Answer:
a = -2
b = 1
c = 5
Step-by-step explanation:
Given:
2a + 4b + c = 5 ............(1)
a - 4b = - 6
or
a = 4b - 6 .............(2)
2b + c = 7
or
c = 7 - 2b ...........(3)
substituting 2 and 3 in 1, we get
2(4b - 6 ) + 4b + (7 - 2b) = 5
or
8b - 12 + 4b + 7 - 2b = 5
or
10b - 5 = 5
or
b = 1
substituting b in 2, we get
a = 4(1) - 6
or
a = -2
substituting b in 3, we get
c = 7 - 2(1)
or
c = 5
thus,
a = -2
b = 1
c = 5
Answer:
sin θ . tan θ
Step-by-step explanation:
Note : -
sec ( - θ ) = sec θ
Formula / Identity : -
sec θ = 1 / cos θ
sec ( - θ ) - cos θ
= [ 1 / cos θ ] - cos θ
{ LCM = cos θ }
= [ 1 / cos θ ] - [ cos²θ / cos θ ]
= [ 1 - cos²θ ] / cos θ
{ 1 - cos²θ = sin²θ }
= sin²θ / cos θ
{ sin²θ = sin θ . sin θ }
= sin θ . sin θ / cos θ
{ sin θ / cos θ = tan θ }
= sin θ . tan θ
Hence, simplified.
