Given a rectangle with side lengths of and , what is its area?

Mathematics

2 answers:

maw [93]3 years ago

8 0

B = 2x+4
H = 3x-5

A = bh
= (2x+4)(3x-5)
= (2x)(3x)+(2x)(-5)+(4)(3x)+(4)(-5)
= 6x^2 - 10x + 12x - 20
= 6x^2 + 2x - 20

So the answer is A (6x^2 + 2x - 20) (i think)

Norma-Jean [14]3 years ago

4 0

I hope this helps you

rectangles area = length × width

area = (2x+4)(3x-5)

area = 2x.3x-2x.5+4.3x-4.5

area = 6x²+2x-20

last one is your answer

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