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elena-14-01-66 [18.8K]
4 years ago
12

Plz help ! Solve by adding or subtracting.

Mathematics
2 answers:
Karolina [17]4 years ago
8 0

Firstly, add x+y=-10 and 2x-y=-8 to get 3x=-18 . From here you can solve for x.


For this, all you need to do is divide 3 on each side, and your answer will be x=-6



To solve for y, just replace x for -6 in either equation and solve.


-6+y=-10\\ y=-4


In short, x = -6 and y = -4.

pav-90 [236]4 years ago
6 0

x + y = -10

2x - y = -8

-----------------Add

3x = -18

x = -6


Substitute x = -6 into x + y = -10

x + y = -10

-6 + y = -10

y = -4


Answer

x = - 6 and y = - 4

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Lucy made $132 for 11 hours of work.
OlgaM077 [116]

Answer:

132/11 = 12

204/12 = 17

17 hours

4 0
3 years ago
What is the simplified form of (12-4t)/(t^2-2t-3)? State any excluded values
nexus9112 [7]

Answer:

<em>Solution; - 4 / t + 1</em>

Step-by-step explanation:

See procedure below;

( 12 - 4t ) / ( t^2 - 2t - 3 ) ⇒ Factor out common term - 4 in 12 - 4t,

- 4 * ( t - 3 ) / ( t^2 - 2t - 3 ) ⇒ Break bottom expression into groups,

- 4 * ( t - 3 ) / ( t^2 + t ) + ( - 3t - 3  ) ⇒ Factor out t from t^2 + t,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3t - 3 ) ⇒ Factor out - 3 from - 3t - 3,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3 * ( t + 1 ) ) ⇒ Factor out common term t + 1,

- 4 * ( t - 3 ) / ( t + 1 ) * ( t - 3 ) ⇒ Cancel out like term t - 3,

<em>Solution; - 4 / t + 1</em>

3 0
3 years ago
State the postulate or theorem you would use to prove each pair of triangles congruent. If the triangles cannot be proved congru
shepuryov [24]
You would use the SSS, ASA, AAS, RHS theorems to prove two triangles to be congruent.
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Given that Segment BE is 5 units, find the indicated measures for each
zalisa [80]

Answer:

The indicated measure of the length of AE = 5 units

Step-by-step explanation:

To determine:

What is the indicated measure of length?

Information Fetching and Solution Steps:

From this single diagram, it seems the indicated measure of length which we have to determine is the length of AE.

Given that Segment BE is 5 units. i.e. BE = 5 units

  • As the square has two equal diagonals AC and DB which meet at point E.
  • So, point E being the common mid-point of both diagonals.

As both of the diagonals of square are equal in length.

And the length of BE is 5 units, which is half the length of BD. It means the diagonal BD has a length of 10 units.

And since both diagonals  AC and DB are equal in length, it means the length of AC must be 10 units.

Since, AC has the length of 10 units, it means the length of AE must be half of the length of AC. Thus, the indicated measure of the length of AE is 5 units.

Therefore, the indicated measure of the length of AE = 5 units

Keywords: square, diagonals, length, line segment

Learn more about square diagonals from brainly.com/question/628263

#learnwithBrainly

6 0
3 years ago
If the sales tax rate is 7.25% in California, then how much would you pay in Los Angeles for a coat that cost $120.00?
S_A_V [24]
120(.0725)=8.70
120+8.70=128.70
8 0
3 years ago
Read 2 more answers
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