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3 years ago

6

What is 23.5 in word form

2 answers:

3241004551 [841]3 years ago

6 0

To hundred three hundred and five

Xelga [282]3 years ago

6 0

Twenty three point five

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Of the 125 guests invited to a wedding, 100 attended the wedding. What percent of the invited guests attended the wedding?

RSB [31]

100/125 * 100 = 80 % (80 percent)

6 0

2 years ago

I need the 68th term help plz

Svet_ta [14]

Answer:

Since -14 is added in each term

Therefore,in 68 th term will be 68×-14 +(-19)

As the 1 st term is -19

68 th term= -952+(-19)

68 th term= -971

8 0

3 years ago

A)<br>be<br>85°<br>120°<br>(2x - 10°<br>X

Lunna [17]

Let's see what to do buddy...

_________________________________

Step (1)

We know that the sum of the interior angles of any n-sided figure is obtained from the following equation :

$(n - 2) \times 180$

Our figure has 5 sides ;

So , sume the interior angles of it equals :

$(5 - 2) \times 180 = 3 \times 180 = 540 \\$

_________________________________

Step (2)

First look at the photo which I post.

According it we have :

$(180 - x) + 120 + 85 + (2x - 10) + 90 = 540 \\$

$2x - x + 475 - 10 = 540$

$x + 465 = 540$

Subtract the sides of the equation minus 465 :

$x = 540 - 465$

$x = 75$

_________________________________

And we're done.

Thanks for watching buddy good luck.

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3 0

3 years ago

0.06 or 0.06666666666 As a fraction

garik1379 [7]

0.06 = 6/100
When simplified, that's 3/50 .

0.06666666666 = 6,666,666,666/10,000,000,000
When simplified, that's 3,333,333,333/5,000,000,000 .

8 0

3 years ago

Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3

Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

$f(x)=x^4-2ax^3+ax^2- x+k$

and

$f(-1)=3$

Answer:

$k = -2$ and $a=1$

Step-by-step explanation:

Given

$f(x)=x^4-2ax^3+ax^2- x+k$

$Factor:\ x - 4$

$f(-1)=3$

Required

Find a and k

For $f(-1)=3$

Substitute -1 for x

$f(x)=x^4-2ax^3+ax^2- x+k$

$f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k$

$f(-1) = 1 - 2a *-1 + a*1 +1 + k$

$f(-1) = 1 +2a + a +1 + k$

$f(-1) = 2 +3a + k$

Substitute 3 for f(-1)

$3 = 2 +3a + k$

Collect Like Terms

$3 - 2 = 3a + k$

$1 = 3a + k$

Also:

If $x - 2$ is a factor, then

$f(2) = 0$

Substitute 2 for x and 0 for f(x)

$f(x)=x^4-2ax^3+ax^2- x+k$

$0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k$

$0 = 16 - 2a * 8 + a * 4 - 2 + k$

$0 = 16 - 16a + 4a - 2 + k$

$0 = 16 - 12a - 2 + k$

Collect Like Terms

$2 - 16 = - 12a + k$

$-14 = k - 12a$

$k = 12a - 14$

Substitute 12a - 14 for k in $1 = 3a + k$

$1 = 3a + 12a - 14$

$1 = 15a - 14$

Collect Like Terms

$15a = 1 + 14$

$15a = 15$

Solve for a

$a = \frac{15}{15}$

$a=1$

Substitute 1 for a in $k = 12a - 14$

$k = 12 * 1 - 14$

$k = 12 - 14$

$k = -2$

3 0

2 years ago