Answer:
The values of 
and 
for a linear system with infinitely many solutions are -2 and 5, respectively.
Step-by-step explanation:
Let 
, if this linear system has infinitely many solutions, then the following conditions must be met:
and 
.
and
The values of and for a linear system with infinitely many solutions are -2 and 5, respectively.
Answer:
x^2-x-5
Step-by-step explanation:
1. expand the square
(+1)(+1)−3(+2)
2. distribute
(+1)+1(+1)−3(+2)
3. distribute
^2++1(+1)−3(+2)
4. multiply by 1
^2+++1−3(+2)
5. combine like terms
^2+2+1−3(+2)
6. distribute
^2+2+1−3−6
7. subtract the numbers
^2+2−5−3
8. combine like terms
^2−−5
9. gg you are done
^2−−5
X= -0.6.........no work needed there is no equation
K is whatever you want it to be
