Of the 125 guests invited to a wedding, 100 attended the wedding. What percent of the invited guests attended the wedding?

Determine the value of X<br><br> AB is the mid segment of triangle LMN. Determine the value of X

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

Since ,AB is the mid segment of triangle LMN

Then

$\Longleftrightarrow AB=\frac{MN}{2}$

$\Longleftrightarrow x+8=\frac{5x+4}{2}$

$\Longleftrightarrow 2\times(x+8)=5x+4$

$\Longleftrightarrow 2x+16=5x+4$

$\Longleftrightarrow 16-4=5x-2x$

$\Longleftrightarrow 3x=12$

$\Longleftrightarrow x=\frac{12}{3}=4$

7 0

2 years ago

Find the area of the polygon.<br>A)125ft<br>B)140ft<br>C)165ft<br>D)345ft

jek_recluse [69]

Answer is C here is why hope. This helps

8 0

3 years ago

Read 2 more answers

A plane intersects one nappe of a double-napped cone such that it is perpendicular to the vertical axis of the cone and it does

Colt1911 [192]

There is two possible conic section that can be formed when the plane intersects the vertical axis, a circle, and an ellipse. Cutting one nappe of double napped cone perpendicular to the vertical axis means the cut is straight across the cone making a right angle. The conic section formed would be a circle.

7 0

3 years ago

Read 2 more answers

A manufacturer reported a sample mean = 22.0 g and a sample standard deviation = 2.5 g based on a sample of 20 of their products

tester [92]

Answer:

$n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5$

So the answer for this case would be n=5 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=22$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.5 represent the sample standard deviation

n represent the sample size

ME = 2 represent the margin of error accepted

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (2)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (3)

We can use as estimator for the population deviation the sample deviation $\hat \sigma = s$

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got $z_{\alpha/2}=1.640$ , replacing into formula (3) we got:

$n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5$

So the answer for this case would be n=5 rounded up to the nearest integer

6 0

3 years ago

Please Help!!! . . . . .

Ede4ka [16]

PEMDAS. parenthesis, exponents, multiple or divide (whichever come first from left to right), add or subtract (whichever comes first from left to right)

So first do stuff in parenthesis.
Then do divide because thats next on the list and it happens earlier than the multiply one.

So, A

8 0

2 years ago