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marshall27 [118]
3 years ago
14

answer for louis wants to carpet the rectangular floor of his basement. the basement has an area of 864 square feet. the width o

f the basement is 2/3its length. what is the length of louis's basement?
Mathematics
1 answer:
AnnZ [28]3 years ago
6 0
Area=legnth times width
width=2/3 legnth
w=2/3l
a=lw
subsitute
a=l(2/3l)
a=864
864=2/3l^2
multiply both sides by 3/2 to clear fraction
2592/2=l^2
1296=l^2
square root both sides
36=legnth

width=2/3 legnth
width=2/3 times 36
width=72/3=24

legnth =36 feet
width=24 feet
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Answer:

The y-intercept is 25000 . The intercept is the fixed cost of the doughnut selling company.

Step-by-step explanation:

In the question, it is given that the fixed cost is $25000 and the expense to produce each doughnut is $0.25.

It is required to find and identify the y intercept.

To do so, use the equation derived in previous part of the exercise to interpret the slope. Compare the equation with standard equation of the line.

Step 1 of 1

The total cost of the company is the sum of fixed cost and the expenses for the doughnut, C=0.25x+25000.

Compare the equation with general linear equation y=mx+c.

The y-intercept is 25000 .

The intercept is the fixed cost of the doughnut selling company.

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2 years ago
Log (3x+1) - Log (2x+5)= 1​
sleet_krkn [62]

Answer:

\huge \red { \boxed{x =  -  \frac{49}{17}}}

Step-by-step explanation:

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3 years ago
Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh
Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver         Manufacturer A               Manufacturer B

   1                      32                                       28

  2                      27                                       22

  3                      26                                       27

  4                      26                                       24

  5                      25                                       24

  6                      29                                       25

  7                       31                                       28

  8                      25                                       27

Let \mu_1 = mean MPG for the fuel efficiency of Manufacturer A brand

\mu_2 = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, H_0 : \mu_1-\mu_2=0  or  \mu_1= \mu_2    {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, H_A : \mu_1-\mu_2\neq 0  or  \mu_1\neq  \mu_2   {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                      T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean MPG for manufacturer A = \frac{\sum X_A}{n_A} = 27.625

\bar X_2 = sample mean MPG for manufacturer B =\frac{\sum X_B}{n_B} = 25.625

s_1 = sample standard deviation for manufacturer A = \sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} } = 2.72

s_2 = sample standard deviation manufacturer B = \sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} } = 2.20

n_1 = sample of cars selected from manufacturer A = 8

n_2 = sample of cars selected from manufacturer B = 8

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }   =  \sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2}  }{8+8-2} }  = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u>  =  \frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8}  } }  ~  t_1_4

                                     =  1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

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Gnom [1K]
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He was the 2nd President in the USA.

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