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3 years ago

7

Graph y = 4x-9 please

2 answers:

stiks02 [169]3 years ago

7 0

Answer:

(0, -9) (1, -5)

Step-by-step explanation:

We know from the equation y = 4x -9, that the slope of the line is 4, and the point that the line crosses the y-intercept is at -9. So, your first point would be at (0, -9) and if you go one value over on the x-coordinate, that means the y-coordinate will go 4 up. So your final point will be (1, -5). The point could also be (2, -1), (3, 3), (4, 7), (5, 11), etc.

I Hope That This Helps! :)

Anna007 [38]3 years ago

4 0

Step-by-step explanation:

Just take two random points, always remember ,take x=0 and find his correspondent y

in this case y=4*0-9=-9

first point (0,-9)

second one:

take any x you want, I took 2 randomly, and y will be

y=4*2-9=8-9=-1

second point is (2,-1)

find these points on graph and connect them with a ruler ! And that is the line you are searching for!

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snow_lady [41]

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Step-by-step explanation:

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8 0

3 years ago

Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0

Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2} +11x+15=0$

so

$a=2\\b=11\\c=15$

substitute in the formula

$x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}$

$x=\frac{-11(+/-)\sqrt{121-120}} {4}$

$x=\frac{-11(+/-)\sqrt{1}} {4}$

$x=\frac{-11(+/-)1} {4}$

$x_1=\frac{-11(+)1}{4}=-2.5$

$x_2=\frac{-11(-)1}{4}=-3$

therefore

The roots of the equation are x=-3 and x=-2.5

5 0

3 years ago