Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
just a plain vanilla substitution
Y= 12 - 2x-2x-2x-2x so it will be Ben Ben this d in your mouth ah ah 12=2x
Answer:
a rental car agency charges a flat rate fee of $32.00 plus $3.00 per day to rent a certain car
c = 32 + 3d
another agency charges a fee of $30.50 plus $3.25 per day to rent the same car
c = 30.50 + 3.25d
the number of days for which the cost are the same means
32 + 3d = 30.50 + 3.25d
by solving we find d = 6 days
STEP
1
:
Pulling out like terms
Pull out like factors :
32 - 2x = -2 • (x - 16)
STEP
2
:
Equations which are never true:
2.1 Solve : -2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
2.2 Solve : x-16 = 0
Add 16 to both sides of the equation :
x = 16
