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Viefleur [7K]
4 years ago
10

1. To calculate discretionary money, you ____?

Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
5 0
The answer to this question is letter a 
vagabundo [1.1K]4 years ago
3 0

Answer:

option B

Step-by-step explanation:

To calculate discretionary money, you calculate the difference between your net income and fixed expenses.

Discretionary money is the left with an individual after paying taxes, personal expenses such food, shelter and clothing, etc. The left money can be used for saving, investing, etc. it purely depends upon individual discretion.

hence Option B is correct

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Is there a screenshot that shows the question? It’s impossible to solve this problem without no numbers or any other information…
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The population of a town is 24,000 and is<br> increasing at a rate of 6% per year for 3 years
Rudik [331]
You answer would be 432000 as your answer
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3 years ago
Factor completely, then place the answer in the proper location on the grid.
Tresset [83]
\mathrm{Factor\:out\:common\:term\:}9 \ \textgreater \  9\left(x^4-25y^8\right)

Factor \ \textgreater \  x^4-25y^8

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x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

x^2-5y^4 \ \textgreater \  \mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)
x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

9\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

Hope this helps!
8 0
3 years ago
A rectangular sandbox is surrounded on all sides by a strip of grass that is 5 ft wide on all sides. The length of the sandbox i
kaheart [24]

Answer:

Dimensions:

Length = 13.256m

width = 9.256m

Step-by-step explanation:

Let the length of the sandbox be = l and its width be = w

The length of the sandbox is 4 ft more than the width.

This means that  l = 4 + w ----- equation 1

For the next step, we will be assuming that the strip of grass is a perfect rectangle. The length of the grass strip will be equals to the length of the sandbox.

Area of the grass =  length X width = (4 +w) \times 5= 5(4+w)------ equation 2

The total area for the sandbox and the grass is 189 square feet.

This means that

(w \times (4+w)) + 5(4+w)=189\\w^2+4w+20+5w=189\\w^2+9w-169=0\\w=9.256m

<em>(Kindly note that the positive value for the width was chosen as length cannot be negative).</em>

Now that we have our width, we can put this into equation 1 to get the length.

l=9.256+4=13.256m

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