Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
Answer:
D) 2x<u>2</u>
Step-by-step explanation:
i got i right on the test
That sir would be I think its y=mx+b
Exterior angle theorem
16x - 7 = 8x + 2 + 10x - 19 ===> 16x -7 = 18x - 17
16x - 16x - 7 = 18x - 16x - 17 ===> -7 = 2x - 17
-7 + 17 = 2x - 17 + 17 ===> 10 = 2x ======> 5 = x
Plug x in to each equation.
Angle P: 8(5) + 2 = 42 deg, Angle Q: 10(5) - 19 = 31
The sum of interior angles = 180. 180 - 42 -31 = 107 deg (angle of PRQ)
To check that line other angle : 16(5) -7 = 73 deg + 107 = 180 deg
Answer:
B
Step-by-step explanation:
The value of the 4 in 14.8 is 10 times the value of the 4 in 3.46.
