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icang [17]
4 years ago
15

An executive in an engineering firm earns a monthly salary plus bonus of 5700 dollars. If she earns a total of 91400 dollars per

year. What is her monthly salary in dollars
Mathematics
1 answer:
Ray Of Light [21]4 years ago
6 0

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equation:

12S + 5700 = 91400

where S is the monthly salary. Solving for S will give us the answer:

12S = 85700

S = 7141.67

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For flvs math 7th grade, there is and end of course segment 2 review video, and there is a phrase in it that we need to tell the
alexandr402 [8]

Answer:

whos ur math teacher

Step-by-step explanation:

3 0
3 years ago
you are considering 2 jobs. one job pays $250 per week, plus 4.5% commission on all sales. The second job pays $1,800 per month
Hoochie [10]
The correct answer is A. Not only does $250 a week equal $1000 a month but the commission is also higher.

first job: $250wk = $1000 Month + .045 commission 
= $12000 year + .045 commission 
second job = $1800 Month + .03 commission 
= $21600 year + .03 commission 
commission based on sales of $1,000,000 

1,000,000 times .045 = $45000 
1,000,000 times .030 = $30000 

FIRST JOB: $12,000 + $45,000 = $57,000 
SECOND JOB: $21,600 + $30,000 = $51,600 

The answer is definitely A.
5 0
3 years ago
0.45m-9=0.9m, what is the least power of ten you could multiply by to write an equivalent equation with integer coefficients?
tia_tia [17]

Answer:

m = -20

Step-by-step explanation:

Step 1 :

9

Simplify ——

10

Equation at the end of step 1 :

45 9

((——— • m) - 9) - (—— • m) = 0

100 10

Step 2 :

9

Simplify ——

20

Equation at the end of step 2 :

9 9m

((—— • m) - 9) - —— = 0

20 10

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 20 as the denominator :

9 9 • 20

9 = — = ——————

1 20

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

9m - (9 • 20) 9m - 180

————————————— = ————————

20 20

Equation at the end of step 3 :

(9m - 180) 9m

—————————— - —— = 0

20 10

Step 4 :

Step 5 :

Pulling out like terms :

5.1 Pull out like factors :

9m - 180 = 9 • (m - 20)

Calculating the Least Common Multiple :

5.2 Find the Least Common Multiple

The left denominator is : 20

The right denominator is : 10

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 2 1 2

5 1 1 1

Product of all

Prime Factors 20 10 20

Least Common Multiple:

20

Calculating Multipliers :

5.3 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

5.4 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 9 • (m-20)

—————————————————— = ——————————

L.C.M 20

R. Mult. • R. Num. 9m • 2

—————————————————— = ——————

L.C.M 20

Adding fractions that have a common denominator :

5.5 Adding up the two equivalent fractions

9 • (m-20) - (9m • 2) -9m - 180

————————————————————— = —————————

20 20

Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

-9m - 180 = -9 • (m + 20)

Equation at the end of step 6 :

-9 • (m + 20)

————————————— = 0

20

Step 7 :

When a fraction equals zero :

7.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-9•(m+20)

————————— • 20 = 0 • 20

20

Now, on the left hand side, the 20 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-9 • (m+20) = 0

Equations which are never true :

7.2 Solve : -9 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3 Solve : m+20 = 0

Subtract 20 from both sides of the equation :

m = -20

One solution was found :

m = -20

6 0
3 years ago
Please help it’s due
vampirchik [111]

Answer:

x = 27.8, y = 35

Step-by-step explanation:

Angle D is equal to Angle A

Angle E is equal to Angle B

Angle F is equal to Angle C

So you can set those equal to each other:

2y - 5 = 65

2y = 70

y = 35

-------------------------

2x + y = 90.6

2x + 35 = 90.6

2x = 55.6

x = 27.8

6 0
4 years ago
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
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