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Korvikt [17]
4 years ago
14

Leila says that 75% of a number will always be greater than 50% of any other number. Complete one inequality to support Leila's

claim and one to show that she is incorrect
Mathematics
2 answers:
saveliy_v [14]4 years ago
5 0
<h2>Answer with explanation:</h2>

Let a and be two numbers.

Leila says that 75% of a number will always be greater than 50% of any other number.

This means that:

                   0.75×a > 0.50×b

( Since 75% of a=0.75×a

and 50% of b =0.50×b )

1)

Numbers that support Leila's claim.

Let a=100 and b=10

0.75×a=0.75×100=75

and 0.50×10=5

As we know that:

               75 > 5

Hence, a=100 and b=10 support Leila's claim.

2)

Numbers that refutes her claim.

Let a=1 and b=200

0.75×a=0.75×1=0.75

and 0.50×200=100

As we know that:

               0.75 < 100

Hence, a=1 and b=200 refutes Leila's claim.

babunello [35]4 years ago
4 0
Supporting claim :
75% of 100 = 0.75 * 100 = 75
50% of 100 = 0.50 * 100 = 50
0.75(100) > 0.50(100) <== ur inequality

counter claim :
75% of -100 = 0.75 * -100 = -75
50% of -100 = 0.50 * -100 = -50
0.75(-100) < 0.50(-100) <== ur inequality


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7 0
3 years ago
Brent claims that more students at his school prefer hot dogs over hamburgers. His friend Shaun doesn’t agree. To settle their a
photoshop1234 [79]

Answer:

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Explanation:

To prove that the results are influenced by <em>gender</em> you can calculate both the probability of preferring hot dogs and the conditional probability of preferring a hot dog given that is a female.

If the two results are different the probability of preferring hot dog is dependent on whether the person is a female or a male.

The probability of preferring hot dogs given that is a female is stated by the problem: 34.2%.

The probability of preferring hot dogs by the whole sample is:

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Thus, the probability of preferring hot dogs given that the student is a female (34.2%) is different from the probability of preferring hot dog for the whole sample, making the results dependent of the gender.

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