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svet-max [94.6K]
3 years ago
13

I NEED HELP PLEASE :(

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

7/8

Step-by-step explanation:

power of 1/2 is the same as square root.

√(49/64) = 7/8 since 7/8 * 7/8 = 7*7/8*8 = 49/64

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Given the diameter of a circle is 17 1/2cm, find its area. (use π=22/7)​
Leokris [45]

Step-by-step explanation:

a

area \: of \: circle = \pi{r}^{2}  \\  = 22 \div 7{ \times (35 \div 2)}^{2}  \\  = 3.14 \times 306.25 \\  = 961.625 {cm}^{2}

<h2>hope it helps.</h2><h2>stay safe healthy and happy...</h2>
6 0
2 years ago
Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply. For any value of x, g(x) will alway
Juli2301 [7.4K]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained
Reptile [31]

Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

The expected value of a negative binomial is the reciprocal of its success probability <em>p.</em>

<em>E(X)=</em>1/<em>p</em>

At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

<em>E(X)=</em>1/<em>p</em>

<em>E(X1)</em>=1

After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (<em>p</em>=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

<em>E(X)=</em>E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

<em>E(X)=</em>1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

<em>E(X)</em>= 29.29

Note: Those values in <em>E(X), </em>should be written the way it will in standard algebra ie they should be small.

4 0
3 years ago
Olivia is making scarves each scarf will have 5 rectangles and 2/5 of the rectangles will be purple how many purple rectangles d
Tomtit [17]

Answer:

Out of every 5 rectangles 2 shall be purple.

3 scarves have 3 times 5 rectangles.

Thus they shall be 3 times 2 that are purple.

Step-by-step explanation:

8 0
3 years ago
What is the y-intercept of the line described by the equation below?<br> y = 7x + 4
zlopas [31]

Answer:

The y-intercept is 4

Step-by-step explanation:

y=mx+b

m=the slope

b=the y-intercept

Hope this helps .-.

8 0
3 years ago
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