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docker41 [41]
3 years ago
15

If h(x)=x^2-5x, g(x)=2x, f(x)=3x-2, what is h(f(g(x)))

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Step-by-step explanation:

start from f(g(x))

f(g(x))= 3(g(x)) -2

f(g(x))= 6x -2

h(f(g(x)))=(f(g(x)))² -5(f(g(x)))

h(f(g(x)))=(6x-2)² -5(6x-2)

h(f(g(x)))=36x²-24x+4-(30x-10)

h(f(g(x)))=36x²-24x+4-30x+10

h(f(g(x)))=36x²-54x+14

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mr Goodwill [35]

Answer:

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)] (1)

Where:

O(x,y) - Point of reference.

P(x,y) - Original point.

P'(x,y) - Dilated point.

k - Dilation factor.

By applying this operation, point B becomes point D:

B(x,y) = (0,4), D(x,y) = (0,6)

D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]

D(x,y) = (0,0) + k\cdot (0,4)

(0,6) = (0,0) +(0,4\cdot k)

(0, 6) = (0,4\cdot k)

k = \frac{3}{2}

Lastly, we transform point C into point E by applying the same operation: C(x,y) = (3, 0), O(x,y) = (0,0) and k = \frac{3}{2}

E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]

E(x,y) = \left(\frac{9}{2}, 0 \right)

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

8 0
3 years ago
In a factory eggs are packaged in groups of 12 per box how many can the factory make 1534 eggs
Marianna [84]
127 boxes is the answer

You just divide the number of eggs by 12

I don’t know if this is what you were asking because the question is worded weirdly
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vagabundo [1.1K]

Answer:

See proof below

Step-by-step explanation:

Two triangles are said to be congruent if one of the 4 following rules is valid

  1. The three sides are equal
  2. The three angles are equal
  3. Two angles are the same and a corresponding side is the same
  4. Two sides are equal and the angle between the two sides is equal

Let's consider the two triangles ΔABC and ΔAED.

ΔABC sides are AB, BC and AC

ΔAED sides are AD, AE and ED

We have AE = AC and EB = CD

So AE + EB = AC + CD

But AE + EB = AB and AC+CD = AD

We have

AB of ΔABC  = AD of ΔAED

AC of ΔABC =  AE of ΔAED

Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC

So  triangles ΔABC and ΔAED are congruent

That means all 3 sides of these triangles are equal as well as all the angles

Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that

BC = ED  Proved

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