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docker41 [41]
3 years ago
15

If h(x)=x^2-5x, g(x)=2x, f(x)=3x-2, what is h(f(g(x)))

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Step-by-step explanation:

start from f(g(x))

f(g(x))= 3(g(x)) -2

f(g(x))= 6x -2

h(f(g(x)))=(f(g(x)))² -5(f(g(x)))

h(f(g(x)))=(6x-2)² -5(6x-2)

h(f(g(x)))=36x²-24x+4-(30x-10)

h(f(g(x)))=36x²-24x+4-30x+10

h(f(g(x)))=36x²-54x+14

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2 years ago
What is the equaiton of the line that goes through the point (6,-1) and is parallel to the line represented by the equautions y=
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parallel lines have the same slope


The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"


They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3


You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6


So far we have y=-5/6x + b

We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"


Replace that on the equation y=-5/6x + b and you get

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-1 = -5 +b

4 = b

b = 4


We found b, or the y-intercept


Go back to the equation y = -5/6 x + b and replace this b with the b we just found


y = -5/6x + 4

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