Answer:
C
Explanation:
The place where the lines intersect is between the lines of the graph.
Answer:
The coordinates of E are
.
Step-by-step explanation:
The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.
Vectorially speaking, dilation is defined by the following operation:
(1)
Where:
- Point of reference.
- Original point.
- Dilated point.
- Dilation factor.
By applying this operation, point B becomes point D:
, 
![D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%280%2C0%29%20%2B%20k%5Ccdot%20%5B%280%2C4%29-%20%280%2C0%29%5D)




Lastly, we transform point C into point E by applying the same operation:
,
and 
![E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%280%2C0%29%20%2B%20%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20%5B%283%2C0%29-%280%2C0%29%5D)

The coordinates of E are
.
127 boxes is the answer
You just divide the number of eggs by 12
I don’t know if this is what you were asking because the question is worded weirdly
Answer:
See proof below
Step-by-step explanation:
Two triangles are said to be congruent if one of the 4 following rules is valid
- The three sides are equal
- The three angles are equal
- Two angles are the same and a corresponding side is the same
- Two sides are equal and the angle between the two sides is equal
Let's consider the two triangles ΔABC and ΔAED.
ΔABC sides are AB, BC and AC
ΔAED sides are AD, AE and ED
We have AE = AC and EB = CD
So AE + EB = AC + CD
But AE + EB = AB and AC+CD = AD
We have
AB of ΔABC = AD of ΔAED
AC of ΔABC = AE of ΔAED
Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC
So triangles ΔABC and ΔAED are congruent
That means all 3 sides of these triangles are equal as well as all the angles
Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that
BC = ED Proved