Question

the length of a ping pong table is 3 ft more than twice the width. the area of a ping pong table is 90 ft. what are the dimensions of a ping pong table?

Answer 1

Answer: 6ft by 15 ft

Explanation:

Width = x

Length = 2x + 3

Area = 90 ft²

x(2x + 3) = 90

2x² +3x - 90 = 0

(x - 6) (2x + 15) = 0

x = 6 or x = -15/2

x = 6 ft

2x + 3 = 2 x 6 + 3 = 15 ft

Answer 2

Answer:

Width = 6ft, length = 15 ft

Step-by-step explanation:

We only know that the area of the ping pong table is 90 $ft^{2}$ and that the length of the ping pong table is 3ft more than twice the width. The width of the ping pong table is unknown, so, we can call this x, i.e.

width = x ft, then

length = (2x+3) ft

but the area of a rectangle is given by width×length, so, we should have

x(2x+3)=90

$2x^{2} +3x=90$

$2x^{2}+3x-90=0$

$x^{2}+(3/2)x-45=0$

$(x-6)(x+15/2)=0$

so

x = 6ft = width and

2x+3 = 2(6)+3=15ft=length