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xxMikexx [17]
3 years ago
14

Mr.santos plants beans and squash in the area shown in the model below which expression is equivalent to the sum of the two area

s?

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0

Answer:

I would go with A. 3(4 + 7) acres

Step-by-step explanation:

Easy, the expression is equivalent to the sum of two areas... Beans and the Squash... you just add them all together and you get 33 acres. Add the parenthesis first and then multiply by 3 you get 33

Paladinen [302]3 years ago
7 0

Answer:

the answer is 3(4+7

Step-by-step explanation:

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5 x 1= 5<br> 5x10=50<br> 5x100=500<br> 5x1000= 5000<br><br> What pattern do you notice ?
storchak [24]
Adds a zero each time?
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2 years ago
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Two cylinders are similar. The volume of the larger cylinder is 343 ft³ and the volume of the smaller cylinder is 125 ​​ft³. The
andreev551 [17]
Both cylinder are similar
Volume of a cylinder is πr^2h
if we consider both has same radius as they are similar
Lets say V1 is volume of small cylinder and V2 is volume of big cylinder.
V1/V2=πr^2x5/πr^2xh
125/343=5/h
0.36=5/h
h=5/0.36
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6 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Vivian can type 240 words in 4 minutes. How many words per minute can Vivian type?
Neporo4naja [7]

Answer:

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Step-by-step explanation:

7 0
2 years ago
1. Use the given translation rule to find the image coordinates. Rule: (x, y) –(x - 4, y + 3) A(4,6) →A') and B(-2,3) -→B'().O A
artcher [175]

We have to translate the coordinates using the given rule.

The given rule is (x-4,y+3)

Now we have to translate the point A(4,6) using the given rule.

Then,

A' is (4-4,6+3)=(0,9)

Now the point B(-2,3) is to be transformed.

Then,

B' is (-2-4,3+3)=(-6,6)

Hence the answer is A'(0,9) and B'(-6,6)

4 0
9 months ago
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