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artcher [175]
3 years ago
9

A car holds 16 gallons of gasoline and can travel 312 miles before refueling. Write aC++ program that calculates the number of m

iles per gallon the car gets. Display the result on the screen.
Computers and Technology
1 answer:
IgorC [24]3 years ago
6 0

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables Declaration and initialization

   int no_gallon=16;

   int dis=312;

   // find the miles per gallon

   double mile_gallon=dis/double(no_gallon);

   // print the results

   cout<<"number of gallons: "<<no_gallon<<endl;

   cout<<"distance travel before refueling: "<<dis<<endl;

   cout<<"miles per gallon is: "<<mile_gallon<<endl;

return 0;

}

Explanation:

Declare and initialize the number of gallon and distance travel without refueling. Calculate the miles per gallon by dividing distance with number of gallons.Then print the results.

Output:

number of gallons: 16

distance travel before refueling: 312

miles per gallon is: 19.5

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OUTPUT

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Original order  

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Explanation:

1. All the variables are declared as mentioned in the question.

int k;

   double d;

   string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

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