How to connect xbox one controller

Write a test program that creates two Rectangle objects—one with width 4 and height 40 and the other with width 3.5 and height 3

BARSIC [14]

Answer:

public class Rectangle {

private double width;

private double heigth;

public Rectangle(double width, double heigth) {

this.width = width;

this.heigth = heigth;

}

public double getWidth() {

return width;

}

public void setWidth(double width) {

this.width = width;

}

public double getHeigth() {

return heigth;

}

public void setHeigth(double heigth) {

this.heigth = heigth;

}

public double perimeter(double width, double heigth){

double peri = 2*(width+heigth);

return peri;

}

public double area(double width, double heigth){

double area = width*heigth;

return area;

}

class RectangleTest{

public static void main(String[] args) {

//Creating two Rectangle objects

Rectangle rectangle1 = new Rectangle(4,40);

Rectangle rectangle2 = new Rectangle(3.5, 35.7);

//Calling methods on the first Rectangel objects

System.out.println("The Height of Rectangle 1 is: "+rectangle1.getHeigth());

System.out.println("The Width of Rectangle 1 is: "+rectangle1.getWidth());

System.out.println("The Perimeter of Rectangle 1 is: "+rectangle1.perimeter(4,40));

System.out.println("The Area of Rectangle 1 is: "+rectangle1.area(4,40));

// Second Rectangle object

System.out.println("The Height of Rectangle 2 is: "+rectangle2.getHeigth());

System.out.println("The Width of Rectangle 2 is: "+rectangle2.getWidth());

System.out.println("The Perimeter of Rectangle 2 is: "+rectangle2.perimeter(4,40));

System.out.println("The Area of Rectangle 2 is: "+rectangle2.area(4,40));

}

Explanation:

Firstly A Rectangle class is created with two fields for width and heigth, a constructor and getters and setters the class also has methods for finding area and perimeters
Then a RectangleTest class containing a main method is created and two Rectangle objects are created (Follow teh comments in the code)
Methods to get height, width, area and perimeter are called on each rectangle object to print the appropriate value

5 0

3 years ago

In general, use no more than _____ font types in a worksheet.

jek_recluse [69]

The answer is a.two
In general, use no more than two font types in a worksheet.

4 0

3 years ago

Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a

yaroslaw [1]

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

print(subject+": "+str(score))

if score >= 90 and score <= 100:

print("Letter Grade: A")

elif score >= 80 and score <= 89:

print("Letter Grade: B")

elif score >= 70 and score <= 79:

print("Letter Grade: C")

elif score >= 60 and score <= 69:

print("Letter Grade: D")

elif score >= 0 and score <= 59:

print("Letter Grade: F")

else:

print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

if score >= 90 and score <= 100:

print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

elif score >= 80 and score <= 89:

print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

elif score >= 70 and score <= 79:

print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

elif score >= 60 and score <= 69:

print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

elif score >= 0 and score <= 59:

print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

else:

print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0

3 years ago

Why should a user preview the document before printing?

Margarita [4]

The user should preview a document first to make sure the layout is correct, so as not to waste paper if a font size or layout is incorrect.

5 0

2 years ago

Read 2 more answers

How did technology change the world

Crank

Answer:

Technology has changed the world for the better.

Explanation:

Without technology, many of the things we take for advantage, such as, credit cards, calling people from far distances, heck even being able to call to across the world from where you are right now. Technology has revolutionized many things we use commonly on a day-to-day basis.

3 0

3 years ago

Read 2 more answers