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attashe74 [19]
3 years ago
8

How can I solve this problem?

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0
It's probably 8 actually. Because you measure the AC and the CB and just subtract.
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Finding out how many events can someone attend with the cost of $36
Tcecarenko [31]
They're allowed to join for $15. And for every event, they have to pay $3.

3x = 21

x = 7

Someone who has $36 can attend 7 events.
6 0
3 years ago
Please help me ASAP .......
mariarad [96]

Answer:

<3 ~= <5 - Alternate Interior Angles Theorem

<3 ~= <7 - Corresponding Angles Theorem

<5 ~= <7 - Vertical Angles Theorem

line I || line m - Transitive Property

3 0
3 years ago
The quantity of soda consumed per week at a soda fountain is 34 liters, with a standard deviation of 5.8 liters. If any 80 weeks
Mama L [17]
5.8/ sqrt 80=0.648 I think you are asking for the standard margin 
Hope this works
3 0
3 years ago
Read 2 more answers
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
2,826 rounded to the nearest tenth
jasenka [17]

Answer:

2,826

Step-by-step explanation:

A tenth is the first place value after the decimal point

In this case, 2,826.<u>0</u>0

To round a number to the tenths place, we look at the hundredths place

If the number is 5 or more, we add 1 to the tenths place, and leave the numbers to the right 0's

If the number is 4 or less, we keep the number as it is in the tenths place, and leave the numbers to the right 0's

In this case, the hundredths place is a 0, which is less than 4, so we keep the 0 in the tenths place, and leave the to the right 0's.

Thus, our final answer is 2,826.

8 0
2 years ago
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