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Shalnov [3]
3 years ago
15

The mean of 10,12,16,20,p,26 is 17.Find the value of p.

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
Answer:  " p = 18 " .
__________________________________________________
Explanation:
__________________________________________________
The [arithmetic] mean =
 
{the sum of all the values in the data set} 
        divided by {the number of values in the number set} ; 
__________________________________________________
  → 17 = (<span>10 + 12 + 16 + 20 + 26 + p) / 6 ;  

__________________________________________________
</span>→ (10 + 12 + 16 + 20 + 26 + p)  = 17 * 6 ;

 →     (p + 84) = 102

Subtract "84" from each side of the equation; 
  to isolate "p" on one side of the equation; & to solve for "p" ; 

→ p + 84 – 84 = 102 – 84 ; 

→ p = 18 . 
_________________________________________________

The answer is:
 " p = 18 " .
_________________________________________________
Paha777 [63]3 years ago
3 0
There are 6 numbers total

17 * 6 = 102

10 + 12 + 16 + 20 + 26 = 84

p = 102-84 = 18

p = 18
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2 years ago
SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below
kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em>\sigma<em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, H_0 : \sigma \leq 100     {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, H_A : \sigma<em> </em>> 100     {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

                        T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s^{2} = sample variance =  \frac{\sum (X-\bar X)^{2} }{n-1}  = 13135.8

            n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u>  =  \frac{(20-1)\times 13135.8^{2} }{100^{2} }

                                     =  24.96 ≈ 25

Hence, the value of test statistics is 25.

5 0
3 years ago
573÷3 i feel like i did something wrong with the 27
Tom [10]
You did everything right. The correct answer is 191

Hope this helps
7 0
2 years ago
Read 2 more answers
The average cost of tuition and room and board at a small private liberal arts college is reported to be $8,500 per term, but a
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Answer:

H₀: µ ≤ $8,500; H₁: µ > $8,500

z= +1.645

Step-by-step explanation:

From the given problem  As average cost of tuition and room and board at a small private liberal is less than the financial administrator As hypothesis is true.

As standard deviation is $ 1,200

α = 0.05

H₀: µ ≤ $8,500

if the null hypothesis is true then value for critical z is +1.645.

6 0
2 years ago
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