3 years ago

How can found thw length of arectngle

1 answer:

5 0

If you have the area of the rectangle, then the equation would be A = W*L

Lets say the area is 15 and the width is 3. You don't know what the length is. Just divide 3 into 15 to get 5. Hope this helps!

You might be interested in

Adding Monomials: <br> Need some Help please ?

AleksAgata [21]

Just add the numbers if the letters are the same only I multiplying do you add the exponents

Answer 14 b^5

4 0

3 years ago

An academic adviser wanted to investigate the amount of money spent by students on textbooks. She randomly sampled 25 students a

ladessa [460]

you should try a bar graph!!!

8 0

3 years ago

The product of two fractions that are each between 0 and 1 is also between 0 and 1.Is this true or false?

Ksenya-84 [330]

True

merry Christmas and a happy new year :)

7 0

3 years ago

Read 2 more answers

NO LINKS!! Please help me with this problem

iogann1982 [59]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

$\qquad \sf \dashrightarrow \: 2b = 12$

$\qquad \sf \dashrightarrow \: b = 6$

length of conjugate axis is :

$\qquad \sf \dashrightarrow \: 2a = 8$

$\qquad \sf \dashrightarrow \: a = 4$

Equation of hyperbola ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1$

plug in the values ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1$

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{ {x}^{2} }{ {16}^{} } = 1$

5 0

2 years ago

Read 2 more answers

The ratio of boys to girls is 3:4 and the ratio of girls to adults is 5:7 what is the ratio of children to adults

Ilya [14]

Answer:

the ratio is 12:7 but im not 100% sure

6 0

3 years ago