Question

In an archery competition, each archer shoots 3 arrows at a target. An archer’s score is calculated by measuring each arrow’s distance from the center of the target and finding the mean. One archer has a mean distance of 1.6 inches and a MAD of 1.3 inches in the first round. In the second round, this same archer’s arrows are farther from the center but more consistent. What values for the mean and MAD would fit this description for the second round?

Answer 1

Answer:

Mean: 3 Mad: 1/3

Step-by-step explanation:

First we need to find out the numbers, so to get a mean of 3 we have to get to 9 ebcause there are 3 arrows.

• We have to make sure that the arrows are not too close to the center
• You can have decimals

2nd: Once you find the numbers which are 2.5, 3, and 3.5 you add them together and divide it by 3 to get 3 the mean

3rd: Find the MAD but adding .5 and .5 to get 1 then divide it by 3 and you get 1/3 as the MAD.

Hope this helps!