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3 years ago

What is the fraction 8/36 expressed in lowest terms?

Mathematics

2 answers:

ladessa [460]3 years ago

6 0

Divide both the numerator and denominator by 4:

8 / 4 = 2
36 / 4 = 9

2/9

salantis [7]3 years ago

6 0

The answer is 2/9. hope this helps

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For a confidence level of 85%, find the critical value for a normally distributed variable. The sample mean is normally distribu

const2013 [10]

Answer:

The value is $Z_{\alpha } = 1.439$

Step-by-step explanation:

From the question we are told that

The confidence level is C = 85%

Generally the level of significance is mathematically represented as

$\alpha = (100 - 85 )\%$

$\alpha = 0.15$

Now from the normal distribution table the critical value of $\alpha$ is

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3 years ago

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Neporo4naja [7]

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Step-by-step explanation:

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3 years ago

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Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$

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3 years ago

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SpyIntel [72]

Can you show the mentioned diagram?

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3 years ago

List the numbers that have 18 as a multiple.

nikklg [1K]

1,18
9,2
6,3
2,9

Thank you for the points :)

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2 years ago