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ArbitrLikvidat [17]
3 years ago
8

-3x+10y=-20 -8x+2y=11 elimination method

Mathematics
1 answer:
Semenov [28]3 years ago
5 0
(-75/37, -193/74) is your answer .-.
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A fertilizer has the analysis of 12-24-20. How many pounds of N, P, and K are there in the 3000 lbs. of fertilizer?
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Answer:

W_N=642.857ibs

W_P=1285.714ibs

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Step-by-step explanation:

From the question we are told that:

Ratio of NPK R=12-24-20.

Weight W=3000 lbs

Generally the sum of the ratio is given as

 \sum R=12+24+20

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Generally the Weight of N is mathematically given by

 W_N=\frac{12}{56}*3000

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Generally the Weight of P is mathematically given by

 W_P=\frac{24}{56}*3000

 W_P=1285.714ibs

Generally the Weight of K is mathematically given by

 W_K=\frac{20}{56}*3000

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Step-by-step explanation:

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Step-by-step explanation:

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