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Dimas [21]
2 years ago
15

∠C

Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
7 0

m∠C=m∠Dx=−3x+804x=80x=20

m∠C=x∘<em>=20∘</em>

earnstyle [38]2 years ago
5 0
I’m asking the same question please help us!!! Thank you
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A fraction with a numerator that is greater than or equal to the denominator is an
GarryVolchara [31]
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BD is tangent to circle O at C, m(arc AEC) = 280, and m(arc ACE) = 140. Find m (The figure is not drawn to scale.)
Zepler [3.9K]

Answer:

The correct answer is second option 60°

Step-by-step explanation:

From the figure we can write,

measure of arc AEC = measure of arc AE + measure of CE

measure of arc ACE = measure of AC +  measure of CE

measure of arc AEC + measure of arc ACE = 280 + 140 = 420°

measure of arc AE + measure of CE + measure of AC +  measure of CE = 420

measure of arc AE + measure of CE +  measure of AC = 360°

measure of CE = 420 - 360 = 60°

The correct answer is second option 60°

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2 years ago
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vitfil [10]

Answer:

B and E

Step-by-step explanation:

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RSB [31]

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3 0
3 years ago
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Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

5 0
3 years ago
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