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andrezito [222]
3 years ago
8

Which expressions are equivalent to z + (z+6)?

Mathematics
1 answer:
Crank3 years ago
3 0

Get rid of parenthesis.


z + z + 6


Add common terms together.


2z + 6 is an expresssion equivalent to z + (z+6)


Hope this helps!



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connie made 1 1/3 pounds of trail mix for a hike.Is there a way connie can break up the trail mix into four equal bags without h
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11/3 = 3.67
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3 years ago
At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 36 m
Degger [83]

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Z score is given by:

z = (raw score - mean) / standard deviation

Given mean of 36 minutes and a standard deviation of 3 minutes.

For x = 32:

z = (32 - 36)/3 = -1.33

For x = 37:

z = (37 - 36)/3 = 0.33

P(-1.33 < z < 0.33) = P(z < 0.33) - P(z < -1.33) = 0.6179 - 0.0198 = 0.5981

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

Find out more on equation at: brainly.com/question/2972832

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7 0
2 years ago
(04.05 LC)
Komok [63]

correct answer is option d.

<u>Step-by-step explanation:</u>

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

<u>a. x3 + 3x2 − 5x − 15 </u>

For -\sqrt{3} ,  x^{3} + 3x^{2} -5x -15  ⇒ (-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15 \neq  0 . So, this isn't the one. We move on further!

<u>b. x3 + 2x2 − 3x − 6 </u>

For -\sqrt{3} ,  x^{3} + 2x^{2} -3x -6  ⇒ (-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6  = 0 .

For \sqrt{3} ,  x^{3} + 2x^{2} -3x -6  ⇒ (\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6 = 0.

For 2 ,  x^{3} + 2x^{2} -3x -6  ⇒ (2) ^{3} + 2(2)^{2} -3(2 ) -6\neq 0 . So, this isn't the one. We move on further!

<u>c. x3 − 3x2 − 5x + 15 </u>

For -\sqrt{3} ,  x^{3}- 3x^{2} -5x -15  ⇒ (-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15 \neq  0 . So, this isn't the one. We move on further!

<u>d. x3 − 2x2 − 3x + 6</u>

For -\sqrt{3} ,  x^{3} - 2x^{2} -3x +6  ⇒ (-\sqrt{3}) ^{3} - 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) +6  = 0 .

For \sqrt{3} ,  x^{3} - 2x^{2} -3x +6  ⇒ (\sqrt{3}) ^{3} -2(\sqrt{3} )^{2} -3(\sqrt{3} ) +6 = 0.

For 2 ,  x^{3} - 2x^{2} -3x +6  ⇒ (2) ^{3} - 2(2)^{2} -3(2 ) +6 = 0.

Therefore, correct answer is option d.

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How many five-digit numbers are there for which each digit is either equal to both adjacent ones, or differs from its neighbors
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Answer:

Step-by-step explanation:

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