Ask question

Ask question

All categories

2 years ago

12

The student council set a goal of raising at least $500 in flower sales. So far it has raised $415.

2 answers:

kotegsom [21]2 years ago

8 0

415<500. They need to raise more money.

(I didn't get the question.) 85$ more to go

zzz [600]2 years ago

6 0

Hi There!

Ok, so student council needs 500 dollars from flower sale, and they already have 415, To find how much they need you have to subtract 500-415, your final answer should be 85, so the student council needs $85 dollars more to reach their goal.

Hope This Helps :)

You might be interested in

How many people were in the sample?<br><br><br><br> 45<br> 90<br> 5<br> 10

Nina [5.8K]

10

The x’s represent just the people, and because the bottom line only represents time it doesn’t affect the amount of people.

4 0

2 years ago

Read 2 more answers

The radius of a circle is 10 cm. Find its circumference in terms of pi

sergejj [24]

Answer:

20 pi is the correct answer

5 0

2 years ago

A French class has a total of 31 students. The number of males is 7 more than the number of females. How many males and how many

Inessa05 [86]

Answer:

12

Step-by-step explanation:

5 0

2 years ago

Priya has completed 9 exam questions this is 60% of the questions on the exam. Write an equation representing this situation. Ex

krek1111 [17]

Answer:

9=0.6q where q is the number of questions on the exam.

Step-by-step explanation:

3 0

3 years ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago