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atroni [7]
3 years ago
11

Solve the division equation using the number line.

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

I belive that it would be 1/6

nikdorinn [45]3 years ago
3 0

one sixth is the answer

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What is the correct way to show ?
Ganezh [65]

Answer:

The middle one unless your solving for it its the yellow one

Step-by-step explanation:

3 0
3 years ago
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Joe and his family are flying to Texas. Their plane flies 645 miles at 215 mph. How long does the trip take? Solve and explain
olya-2409 [2.1K]
You can use the distance equation.. d = rt
d = distance = 645
r = rate = 215 mph
t = time = ???? find the time
645 = 215t
645/215 = 215t / 215
3 = t
t = 3
It took 3 hours

7 0
3 years ago
Angle A and angle B are supplementary angles, if angle B equals 73°, what is the measurement of angle A?
balandron [24]
Supplementary means adds to 180
A+B=180
B=73
A+73=180
minus 73 both sides
A+73-73=180-73
A+0=107
A=107

A=107 degrees
7 0
3 years ago
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What is the calculation for determining simple interest and compound interest? Borrowing if borrowed $20,000 for 5 years at a 4%
yarga [219]

Answer:

If using simple interest, the formula is:

= Amount * ( 1 + rate * time)

= 20,000 * ( 1 + 4% * 5)

= $24,000

Interest = Balance after 5 years - Investment

= 24,000 - 20,000

= $4,000

Using Compound Interest:

= Amount * ( 1 + rate)^time

= 20,000 * ( 1 + 4%)⁵

= $24,333.06

Interest = 24,333.06 - 20,000

= $4,333.06

6 0
3 years ago
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
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