The length of segment F'G' is 7 units
<h3>Length</h3>
The length of a line segment is the number of units on the line.
<h3>
Coordinates </h3>
The coordinates are given as:
![F = (-2,-4)](https://tex.z-dn.net/?f=F%20%3D%20%28-2%2C-4%29)
![G = (5,-4)](https://tex.z-dn.net/?f=G%20%3D%20%285%2C-4%29)
<h3>
Distance </h3>
Start by calculating the length of segment FG using the following distance formula
![FG = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B%28x_1%20-%20x_2%29%5E2%20%2B%20%28y_1%20-%20y_2%29%5E2%7D)
So, we have:
![FG = \sqrt{(-2- 5)^2 + (-4+ 4)^2}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B%28-2-%205%29%5E2%20%2B%20%28-4%2B%204%29%5E2%7D)
![FG = \sqrt{49}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B49%7D)
![FG = 7](https://tex.z-dn.net/?f=FG%20%3D%207)
The transformation of segment FG to F'G' is a rigid transformation.
This means that:
The lengths of segments FG and F'G' are the same
So, we have:
![F'G' = 7](https://tex.z-dn.net/?f=F%27G%27%20%3D%207)
Hence, the length of segment F'G' is 7 units
Read more about length at:
brainly.com/question/17206319
Assuming the bases are laid out in a square, then we can use the Pythagorean Theorem to find the distance from home plate to second base.
This distance is exactly the length of the hypotenuse of the right triangle that forms when you split the square along the diagonal. Let this distance be x
Each of the legs are 90 ft, so a = 90 and b = 90. The hypotenuse is c = x for now.
a^2 + b^2 = c^2
90^2 + 90^2 = x^2
8100 + 8100 = x^2
16200 = x^2
x^2 = 16200
sqrt(x^2) = sqrt(16200) ... apply the square root to both sides
x = 127.2792206
x = 127.3 .... round to the nearest tenth (one decimal place)
The final answer is 127.3 feet
Answer:
r=60°
Step-by-step explanation:
Both of the angles together make up 90°. we know this because of the red little box denoting 90°.
If one of the angles is 30°, to find the other one, simply subtract 30 from 90.
90-30=60
r=60°
Answer:
52
Step-by-step explanation:
your mother is not okay
Answer:
The coupon was for 25% off