Hypertonic environment
<h3>
How do salts and sugars preserve food?</h3>
Salts and sugars work to preserve foods by creating a hypertonic environment. Salt and sugar will remove the water from the bacteria or fungi and they will not be able to proliferate. Loss of water results in plasmolysis, or cytoplasmic shrinkage.
<h3>What is hypertonic solution and plasmolysis?</h3>
Compared to another solution, a hypertonic solution has a higher solute concentration.
Plant cells subjected to hyperosmotic stress frequently exhibit plasmolysis as a reaction. The live protoplast violently separates from the cell wall as a result of the loss of turgor. The vacuole is primarily responsible for the plasmolytic process.
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Around 93 million miles (150 million kilometers) away.
Macromolecules are large molecules within your body that serve essential physiological functions<span>. Encompassing </span>carbohydrates<span>, </span>proteins, lipids and nucleic acids<span>, macromolecules exhibit a number of similarities.
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An experiment to test the best conditions for bacteria to grow is the material that the bacteria feed upon. <u>Option D.</u>
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Antibacterial hand soap with different concentrations. Dependent variable bacterial growth as measured by the diameter of the zone of inhibition. Exposing Petri dishes to different temperatures can skew the level of bacterial growth they inhabit. Plant height is the dependent variable that responds to changes in the independent variable.
Sunlight is the controlling variable because each plant is exposed to the same amount of sunlight. It is the dependent variable because it measures the amount of plant growth. The dependent variable depends on the independent variable. How much plants grow depends on how much sun they receive. A continuous increase in temperature from a minimum value increases the rate of bacterial growth because the rate of metabolic reactions increases with increasing temperature.
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Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.