Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
4.56
Step-by-step explanation:
After this equation is simplified, it is solved the way any 1-step linear equation is solved.
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1.4t -0.4(t -3.1) = 5.8 . . . . . . given
1.4t -0.4t +1.24 = 5.8 . . . . . eliminate parentheses
t +1.24 = 5.8 . . . . . . . . . collect terms (now you have a 1-step equation)
t = 4.56 . . . . . . . . . .subtract 1.24
Answer:
y=1, x=1
Step-by-step explanation:
This is a 90-45-45 triangle. One side is a sq root 2, and the other sides are a and a.
For example, if one side was 3 sq root two, then the other sides would be 3 and 3
What do we do? Is there a attachment?
