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Alisiya [41]
3 years ago
11

51 and 53 HELP PLS!!!!!!!

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0
Hi!
Answers:

51. w=9/4

53. b=12
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An acute angle in one right triangle has the same measure as an acute angle in another right triangle. Name the theorem or postu
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Answer:

Step-by-step explanation:

Right Triangle Similarity

Acute Angle Similarity

If one of the acute angles of a right triangle is congruent to an acute angle of another right triangle, then by Angle-Angle Similarity the triangles are similar.

In the figure, ∠M≅∠Y , since both are right angles, and ∠N≅∠Z .

So, ΔLMN∼ΔXYZ .

Leg-Leg Similarity

If the lengths of the corresponding legs of two right triangles are proportional, then by Side-Angle-Side Similarity the triangles are similar.

In the figure,  ABPQ=BCQR .

So, ΔABC∼ΔPQR .

Hypotenuse-Leg Similarity

If the lengths of the hypotenuse and a leg of a right triangle are proportional to the corresponding parts of another right triangle, then the triangles are similar. (You can prove this by using the Pythagorean Theorem to show that the third pair of sides is also proportional.)

In the figure, DFST=DESR .

So, ΔDEF∼ΔSRT .

Taking Leg-Leg Similarity and Hypotenus-Leg Similarity together, we can say that if any two sides of a right triangle are proportional to the corresponding sides of another right triangle, then the triangles are similar.

3 0
3 years ago
Hey, help plz! 9r/sif r = 6 and s = 3?????
slega [8]

Answer:

18

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18

3 0
3 years ago
Help, I don’t understand
Sedbober [7]

Answer:

A=90°,B=90°,C=90°,D=90°

Step-by-step explanation:

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Which graph represents y = |x|? A B C D
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Step-by-step explanation:

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Step-by-step explanation:

px^2-qx+r

p(x^2-q/px)+r

p[(x^2-q/px +(q/2p)^2_(q/2p)^2)]+r

p[(x-q/2p)^2 -q^2/4p^2)]+r

p(x-q/2p)^2 -q^/4p+r

p(x-q/2p)^2-(q^2-4pr)/4p

3 0
3 years ago
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