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3 years ago

Which trigonometric ratio is defined as the length of the adjacent leg divided by the length of the hypotenuse?

Mathematics

2 answers:

AfilCa [17]3 years ago

3 0

SOH CAH TOA

Cosine is adjacent over hypotenuse so you're answer is C.

:)))

weqwewe [10]3 years ago

3 0

Answer:

Step-by-step explanation:

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P − 10p + -5p + 14p − -9p − 2 = -20

djverab [1.8K]

You will need to work left to right.

p - 10p + -5p +14p - -9p - 2 = -20

-9p + -5p +14p - -9p - 2 = -20

-14p +14p - -9p - 2 = -20

0p- -9p - 2 = -20

9p - 2 = -20

Then you will want to eliminate 2 by adding it to both sides

9p = -18

Then divide by 9 to isolate P

p=-2

4 0

2 years ago

Find the inverse function for f(x)=sqrt2x-6 picture below

Olenka [21]

Answer:

y = (x^2 + 6) / 2

Step-by-step explanation:

Original function: $\sqrt{2x - 6}$

To find the inverse of a function we have to switch the x and y values and solve for y again

x = sqrt (2y-6)

To get rid of a square root we square the square root so:

x^2 = 2y-6

Add 6

x^2 + 6 = 2y

Divide by 2

y = (x^2 + 6) / 2

6 0

3 years ago

A train is traveling at a constant speed and goes a distance of 7 1/2 kilometers in 6 minutes the train will continue at this sp

Alla [95]

Answer:

392939939393939399393939393

Step-by-step explanation:

7 0

2 years ago

To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?

romanna [79]

Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is $A=\pi r^2$ and denote the sector area as $A_1$ .
Then $\dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}$ (the ratio between area is the same as the ratio between coresponding angles).

$A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}$ .

6 0

3 years ago

A Square was altered so that one side is increased by 9 inches in the other side is decreased by 2 inches.The area of the result

LekaFEV [45]

Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.

The area of this rectangle is (s+9)(s-2) = 60 in^2.

This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:

s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.

4 0

2 years ago