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3 years ago

Please help I will reward brainly!!!!

Mathematics

1 answer:

matrenka [14]3 years ago

3 0

The second one is correct
It's multiplying by 2

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X and Y are continuous values, both measured to 2 significant figures. X=230 and Y=400. work out the greatest possible value of

kirill115 [55]

"Two significant figures" means that a digit after the second one could actually be anything ... it wasn't measured. 'X' could be anything from 230 to 239. 'Y' could be anything from 400 to 409. The greatest possible value of that fraction is. (239)/(409 squared) .

8 0

3 years ago

You are measuring the height of a Ferris wheel at an amusement

VladimirAG [237]

Answer:

154 ft

Step-by-step explanation:

A right triangle is formed, where the height of the wheel (h) is one leg, the distance between you and the base of the wheel is the other leg, and the distance between you and the top of the wheel is the hypotenuse (the angle included between the last two sides is 51°)

From definition:

tan(51°) = opposite/adjacent

tan(51°) = h/125

h = tan(51°)*125

h = 154 ft

7 0

2 years ago

Pls help urgently extra points and mark brainlist

HACTEHA [7]

Answer:

Last answer

Step-by-step explanation:

5 0

2 years ago

What is Y=3x^2+6x+10 in vertex form.

Nuetrik [128]

Answer:

y=3(x+1)^2+7

Step-by-step explanation:

7 0

2 years ago

Will rate7 you brainliest

Vilka [71]

Answer:

$\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }$

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

$\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)$

$\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)$

$\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)$

$\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)$

Now, let's compute the product.

$\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}$

So the correct answer is the first one.

Thank you.

7 0

3 years ago