Answer:
Volume of cuboid = 300 in³
Surface area of cuboid = 280 in²
Step-by-step explanation:
Given:
Length = 10 in
Width = 5 in
Height = 6 in
Find:
Volume of cuboid
Surface area of cuboid
Computation:
Volume of cuboid = [L][B][H]
Volume of cuboid = [10][5][6]
Volume of cuboid = 300 in³
Surface area of cuboid = 2[lb][bh][hl]
Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]
Surface area of cuboid = 2[50 + 30 + 60]
Surface area of cuboid = 2[140]
Surface area of cuboid = 280 in²
C. f(x) = – 2 cos 6x + 1
Start by determining the amplitude. Since we've deduced the amplitude is 2, the equation can include either a positive or negative 2 (since amplitude measures absolute value).
Next is the period. The equation for period P is P = (2pi)/b. If P is pi/3, then
pi/3 = (2pi)/b. Thus your b value should be 6.
Finally, the midline would be given by + 1 since adding a unit shifts the function upwards. This means that instead of the highest y value being 2 and the lowest -2, instead you'd have values of 3 and -1.
(3 – 1)/2 = 1 (midpoint theory).
