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jeka57 [31]
3 years ago
13

What isthe vertical line test​

Mathematics
2 answers:
Irina-Kira [14]3 years ago
6 0

The vertical line test is a visual way to determine if a curve is a graph of a function or not.

A function can only have one output, y, for each unique input, x. If a vertical line intersects a curve on an xy-plane more than once then for one value of x the curve has more than one value of y, and so, the curve does not represent a function.

If all vertical lines intersect a curve at most once then the curve represents a function.

olya-2409 [2.1K]3 years ago
5 0

answer:

Its when you make lines vertically from every point and if a line hits a points under it is wrong

Step-by-step explanation:

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When finding Area as a Sum can I combine like terms? Example: 1x^2+9x-4x-10
Stolb23 [73]

Answer:

yes

Step-by-step explanation:

because it will be easier if the they are like terms

4 0
3 years ago
Use the distributive property to create an equivalent expression to 7(2j + 3 + 2j).
Scorpion4ik [409]

Answer:

28j + 21

Step-by-step explanation:

combine like terms

7(2j+ 3+ 2j)

7(4j+3)

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6 0
2 years ago
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Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
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Proving the Converse of the Parallelogram Side Theorem
Brrunno [24]

Answer:

do it yourself

Step-by-step explanation:

6 0
2 years ago
Patient A receives 3 times the amount of certain medicine as Patient B. The two doses add to 200 milligrams. What amount of the
4vir4ik [10]
Patient A - 150 mg
Patient B - 50 mg
I hope this helps :)
7 0
3 years ago
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