Answer:
a. 0.4
b. 0.6
c. 0.6493
Step-by-step explanation:
p(checking work email) = p(A) = 0.40
p(staying connected with cell phone) = p(B) = 0.30
p(having laptop) = p(c) = 0.35
p(checking work mail and staying connected with cell phone) = p(AnB) = 0.16
p(neither A,B or C) = p(AuBuC)
= 1-42.8%
= 0.572
p(A|C) = 88% = 0.88
p(C|B) = 70% = 0.7
a. What is the probability that a randomly selected traveler who checks work email also uses a cell phone to stay connected?
p(B|A) = p(AnB)/p(A)
= 0.16/0.4
= 0.4
b. What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected?
p(B|C) = P(C|B)p(B)/p(C)
= 0.7x0.3/0.35
= 0.6
c. If the randomly selected traveler checked work email and brought a laptop, what is the probability that he/she uses a cell phone to stay connected?
p(A|BnC)
= P(BnAnC)/p(AnC)
= p(AnC) = p(A|C).p(C)
= 0.88x0.35
= 0.308
p(AnBnC) = p(AuBuC)-p(a)-p(b)+ p(AnB)+p(AnC)+p(BnC)
p(BnC) = 0.7x0.3
= 0.21
p(AnBnC) = 0.572-0.4-0.3-0.35+0.16+0.308+0.21
= 0.2
p(A|BnC) = 0.2/0.308
= 0.6493
Answer: The boxer lose 1.8 kg in the final week to get able to compete as a flyweight.
Step-by-step explanation:
Since we have given that
Quantity of weight a boxer needs to lose in a month is given by
In 3 months, he lowers his weight from 55.5 kg to 53.8 kg.
So, Quantity of weight he lose in three months is given by
Number of kilograms the boxer lose in the final week to be able to compete as a flyweight is given by
Hence, the boxer lose 1.8 kg in the final week to get able to compete as a flyweight.
The point-slope form:
We have the points (-1, 6) and (3, -2). Substitute:
<h3>Answer:</h3><h3>y - 6 = -2(x + 1) <em>point-slope form</em></h3><h3>y = -2x + 4 <em>slope-intercept form</em></h3><h3>2x + y = 4 <em>standard form</em></h3>
Answer:
576 cm^2
Step-by-step explanation:
16^2 + 2 x 16 x 10
256 + 32 x 10
256 + 320
= 576
use the quadrant system to find the area of the polygon shown
44 square units
54 square units
36 square units
52 square units
True 44 square units
