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Leto [7]
3 years ago
8

Help me out please..

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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What is the value of x?<br><br><br><br> Enter your answer in the box.
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Notice that based on the diagram, all of the sides of the triangle are the same length. (The dashes on the sides of the triangle show that the sides are of congruence.) This means that the triangle is an equilateral triangle. An important thing to note about equilateral triangles is that they all have angles of 60°. All angles in equivalent triangles are 60°.


This means that we can set 7x - 3 equal to 60 to solve for x:

7x - 3 = 60

  • Set up

7x = 63

  • Add 3 to both sides

x = 9

  • Divide both sides by 7

Our answer is x = 9.

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Answer:

15

Step-by-step explanation:

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4 years ago
A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
lana [24]

Answer:

(9)\frac{1}{12}  (10) \frac{1}{12}  (11)\frac{5}{12}  (12)\frac{1}{4}  (13)\frac{1}{6} 14)\frac{5}{36} (15)\frac{1}{12}  (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are:  (3, 6), (4, 5),  (5, 4)

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are:  (1, 3),(2, 2),(3, 1),

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4),  (3, 1), (3, 2), (3, 3),  (4, 1), (4, 2),  (5, 1)

P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6),  (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4),  (5, 5), (6, 6)

P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5),  (3, 4), (4, 3), (5, 2),  (6, 1)

P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}

16.Probability of getting two numbers with a sum of 14.

P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0

4 0
4 years ago
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